document.write( "Question 1056949: Confidence Interval (Please be as Detailed as Possible)\r
\n" ); document.write( "\n" ); document.write( " The lengths (in inches) of 9 fish caught in Falcon Lake are given below:\r
\n" ); document.write( "\n" ); document.write( " 8.8, 33.7, 3.1, 5.1, 28.0, 13.5, 9.5, 12.1, 7.7\r
\n" ); document.write( "\n" ); document.write( "Assume that the distribution of lengths of fish in this lake is normal\r
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\n" ); document.write( "\n" ); document.write( "a. Estimate the true mean length of the fish in this lake with 80% confidence.\r
\n" ); document.write( "\n" ); document.write( " (Hint: the standard deviation of the 9 fish caught is 10.4 inches.)\r
\n" ); document.write( "\n" ); document.write( "b. Write a brief summary interpreting your answer to part (a).
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Algebra.Com's Answer #672036 by Boreal(15235)\"\" \"About 
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The mean is 13.5, the sd is 10.4
\n" ); document.write( "the interval is t(0.90, df=8)*10.4/sqrt (9)=1.397*10.4/3=4.84
\n" ); document.write( "The 80% CI is the mean +/- 4.84 or (5.56,15.24) units inches
\n" ); document.write( "That means we are 80% confident that the true value is in the interval. We don't know the true value and never will, but we are moderately confident it is between 5.56 and 15.24 inches.
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