document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92376>Question 92376</A>: <I><SPAN STYLE=\"word-break: break-all;\"> e^(2x)-e^x=2, Solve for x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67196 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67196\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> e^(2x)-e^x-2=0, Solve for x\r<BR>\n" );
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document.write( "It's a quadratic; factor it:\r<BR>\n" );
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document.write( "(e^x-2)(e^x+1)=0<BR>\n" );
document.write( "e^x = 2 or e^x=-1<BR>\n" );
document.write( "Take the natural log to get:<BR>\n" );
document.write( "x = ln2 or x=ln(-1)<BR>\n" );
document.write( "x = ln2 is the only solution as x=ln(-1) does not exist.\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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