document.write( "Question 1056659: solve.\r
\n" ); document.write( "\n" ); document.write( "sqrt(2x+7)-sqrt(3x-2)=2 \n" ); document.write( "
Algebra.Com's Answer #671886 by Alan3354(69443)\"\" \"About 
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sqrt(2x+7)-sqrt(3x-2)=2
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\n" ); document.write( "sqrt(2x+7) = sqrt(3x-2) + 2
\n" ); document.write( "Square both sides.
\n" ); document.write( "2x+7 = 3x-2 + 4 + 4sqrt(3x-2)
\n" ); document.write( "-x+5 = 4sqrt(3x-2)
\n" ); document.write( "Square again
\n" ); document.write( "x^2-10x+25 = 16(3x-2) = 48x-32
\n" ); document.write( "x^2 - 58x + 57 = 0
\n" ); document.write( "(x - 1)*(x - 57) = 0
\n" ); document.write( "x = 1
\n" ); document.write( "x = 57
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\n" ); document.write( "For 57:
\n" ); document.write( "sqrt(121) - sqrt(169) = 2 --> not using the principal sqrt.
\n" ); document.write( "ie, -11 - (-13) = 2\r
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