document.write( "Question 1056804: Prove the identity:\r
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Algebra.Com's Answer #671870 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"cot%5E%22%22%28A%29\"\"%22%22-%22%22\"\"tan%5E%22%22%28A%29\"\"%22%22=%22%22\"\"2cot%5E%22%22%282A%29\"\r\n" );
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document.write( "Work with the right side:\r\n" );
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document.write( "\"2cot%5E%22%22%282A%29\"\r\n" );
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document.write( "\"2%5E%22%22%2Ftan%5E%22%22%282A%29\"\r\n" );
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document.write( "\"2\"\"%22%F7%22\"\"tan%5E%22%22%282A%29\"\r\n" );
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document.write( "Use formula for tan(2A)\r\n" );
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document.write( "\"2\"\"%22%F7%22\"\"%28%282tan%5E%22%22%28A%29%29%2F%281-tan%5E2%28A%29%29%29\"\r\n" );
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document.write( "Invert the second and multiply:\r\n" );
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document.write( "\"2\"\"%22%D7%22\"\"%28%281-tan%5E2%28A%29%29%2F2tan%5E%22%22%28A%29%29%29\"\r\n" );
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document.write( "\"cross%282%29\"\"%22%D7%22\"\"%28%281-tan%5E2%28A%29%29%2Fcross%282%29tan%5E%22%22%28A%29%29%29\"\r\n" );
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document.write( "\"%281-tan%5E2%28A%29%29%2Ftan%5E%22%22%28A%29%29\"\r\n" );
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document.write( "Break into two fractions:\r\n" );
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document.write( "\"1%5E%22%22%2Ftan%5E%22%22%28A%29\"\"%22%22-%22%22\"\"tan%5E2%28A%29%2Ftan%5E%22%22%28A%29\"\r\n" );
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document.write( "\"cot%5E%22%22%28A%29\"\"%22%22-%22%22\"\"tan%5Ecross%282%29%28A%29%2Fcross%28tan%5E%22%22%28A%29%29\"\r\n" );
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document.write( "\"cot%5E%22%22%28A%29\"\"%22%22-%22%22\"\"tan%5E%22%22%28A%29\"\r\n" );
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document.write( "Edwin
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