document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1056626>Question 1056626</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Jurassic Zoo charges &#8203;$7 for each adult admission and &#8203;$4 for each child. \r<BR>\n" );
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document.write( "The total bill for the 101 people from a school trip was $491.00. \r<BR>\n" );
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document.write( "How many adults and how many children went to the&#8203; zoo? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671818 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671818\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let a be each adult admission, and y be  each child. Then:<BR>\n" );
document.write( "a+y=101<BR>\n" );
document.write( "7a+4y=491;<BR>\n" );
document.write( "4a+4y=404<BR>\n" );
document.write( "3a=87<BR>\n" );
document.write( "a=29<BR>\n" );
document.write( "y=72<BR>\n" );
document.write( "There were 29 adult admissions; and 72 child's. &#9786;&#9786;&#9786;&#9786;\r<BR>\n" );
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document.write( "Addendum: If a+y=101, multiplying the whole equation by 4, we get 4a+4y=404!!!!&#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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