document.write( "Question 92333: solve the system by substitution\r
\n" ); document.write( "\n" ); document.write( " x + y = 12
\n" ); document.write( " -x + y = 2
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Algebra.Com's Answer #67180 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a linear system of equations by subsitution

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"1%2Ax%2B1%2Ay=12\"
\n" ); document.write( " \"-1%2Ax%2B1%2Ay=2\"
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\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
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\n" ); document.write( " Solve for y for the first equation
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\n" ); document.write( " \"1%2Ay=12-1%2Ax\"Subtract \"1%2Ax\" from both sides
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\n" ); document.write( " \"y=%2812-1%2Ax%29\" Divide both sides by 1.
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\n" ); document.write( " Which breaks down and reduces to
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\n" ); document.write( " \"y=12-1%2Ax\" Now we've fully isolated y
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\n" ); document.write( " Since y equals \"12-1%2Ax\" we can substitute the expression \"12-1%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
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\n" ); document.write( " \"-1%2Ax%2B1%2Ahighlight%28%2812-1%2Ax%29%29=2\" Replace y with \"12-1%2Ax\". Since this eliminates y, we can now solve for x.
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\n" ); document.write( " \"-1%2Ax%2B1%2A%2812%29%2B1%28-1%29x=2\" Distribute 1 to \"12-1%2Ax\"
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\n" ); document.write( " \"-1%2Ax%2B12-1%2Ax=2\" Multiply
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\n" ); document.write( " \"-1%2Ax%2B12-1%2Ax=2\" Reduce any fractions
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\n" ); document.write( " \"-1%2Ax-1%2Ax=2-12\" Subtract \"12\" from both sides
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\n" ); document.write( " \"-1%2Ax-1%2Ax=-10\" Combine the terms on the right side
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\n" ); document.write( " \"-2%2Ax=-10\" Now combine the terms on the left side.
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\n" ); document.write( " \"cross%28%281%2F-2%29%28-2%2F1%29%29x=%28-10%2F1%29%281%2F-2%29\" Multiply both sides by \"1%2F-2\". This will cancel out \"-2%2F1\" and isolate x
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\n" ); document.write( " So when we multiply \"-10%2F1\" and \"1%2F-2\" (and simplify) we get
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\n" ); document.write( " \"x=5\" <---------------------------------One answer
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\n" ); document.write( " Now that we know that \"x=5\", lets substitute that in for x to solve for y
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\n" ); document.write( " \"-1%285%29%2B1%2Ay=2\" Plug in \"x=5\" into the 2nd equation
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\n" ); document.write( " \"-5%2B1%2Ay=2\" Multiply
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\n" ); document.write( " \"1%2Ay=2%2B5\"Add \"5\" to both sides
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\n" ); document.write( " \"1%2Ay=7\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F1%29%281%29%29%2Ay=%287%2F1%29%281%2F1%29\" Multiply both sides by \"1%2F1\". This will cancel out 1 on the left side.
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\n" ); document.write( " \"y=7%2F1\" Multiply the terms on the right side
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\n" ); document.write( " \"y=7\" Reduce
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\n" ); document.write( " So this is the other answer
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\n" ); document.write( " \"y=7\"<---------------------------------Other answer
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\n" ); document.write( " So our solution is
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\n" ); document.write( " \"x=5\" and \"y=7\"
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\n" ); document.write( " which can also look like
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\n" ); document.write( " (\"5\",\"7\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"1%2Ax%2B1%2Ay=12\"
\n" ); document.write( " \"-1%2Ax%2B1%2Ay=2\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"1%2Ax%2B1%2Ay=12\" (red) and \"-1%2Ax%2B1%2Ay=2\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
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\n" ); document.write( " and we can see that the two equations intersect at (\"5\",\"7\"). This verifies our answer.
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\n" ); document.write( " Check:
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\n" ); document.write( " Plug in (\"5\",\"7\") into the system of equations
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\n" ); document.write( " Let \"x=5\" and \"y=7\". Now plug those values into the equation \"1%2Ax%2B1%2Ay=12\"
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\n" ); document.write( " \"1%2A%285%29%2B1%2A%287%29=12\" Plug in \"x=5\" and \"y=7\"
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\n" ); document.write( " \"5%2B7=12\" Multiply
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\n" ); document.write( " \"12=12\" Add
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\n" ); document.write( " \"12=12\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"5\",\"7\") satisfies \"1%2Ax%2B1%2Ay=12\"
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\n" ); document.write( " Let \"x=5\" and \"y=7\". Now plug those values into the equation \"-1%2Ax%2B1%2Ay=2\"
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\n" ); document.write( " \"-1%2A%285%29%2B1%2A%287%29=2\" Plug in \"x=5\" and \"y=7\"
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\n" ); document.write( " \"-5%2B7=2\" Multiply
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\n" ); document.write( " \"2=2\" Add
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\n" ); document.write( " \"2=2\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"5\",\"7\") satisfies \"-1%2Ax%2B1%2Ay=2\"
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\n" ); document.write( " Since the solution (\"5\",\"7\") satisfies the system of equations
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\n" ); document.write( " \"1%2Ax%2B1%2Ay=12\"
\n" ); document.write( " \"-1%2Ax%2B1%2Ay=2\"
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\n" ); document.write( " this verifies our answer.
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