document.write( "Question 1056731: If y is inversely proportional to the square of x and has a value of 901 when x is 211, find y when x is 103. \n" ); document.write( "
Algebra.Com's Answer #671794 by Boreal(15235)\"\" \"About 
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y=k/x^2
\n" ); document.write( "901=k/211^2
\n" ); document.write( "k=901*211^2=40,113,421
\n" ); document.write( "Put into the second
\n" ); document.write( "y=40,113,421/103^2
\n" ); document.write( "y=3781.07
\n" ); document.write( "
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