document.write( "Question 92332: please help I am having trouble with this problem.\r
\n" ); document.write( "\n" ); document.write( "x + y = 4
\n" ); document.write( "-x +y =2
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Algebra.Com's Answer #67179 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a linear system of equations by subsitution

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"1%2Ax%2B1%2Ay=4\"
\n" ); document.write( " \"-1%2Ax%2B1%2Ay=2\"
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\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
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\n" ); document.write( " Solve for y for the first equation
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\n" ); document.write( " \"1%2Ay=4-1%2Ax\"Subtract \"1%2Ax\" from both sides
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\n" ); document.write( " \"y=%284-1%2Ax%29\" Divide both sides by 1.
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\n" ); document.write( " Which breaks down and reduces to
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\n" ); document.write( " \"y=4-1%2Ax\" Now we've fully isolated y
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\n" ); document.write( " Since y equals \"4-1%2Ax\" we can substitute the expression \"4-1%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
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\n" ); document.write( " \"-1%2Ax%2B1%2Ahighlight%28%284-1%2Ax%29%29=2\" Replace y with \"4-1%2Ax\". Since this eliminates y, we can now solve for x.
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\n" ); document.write( " \"-1%2Ax%2B1%2A%284%29%2B1%28-1%29x=2\" Distribute 1 to \"4-1%2Ax\"
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\n" ); document.write( " \"-1%2Ax%2B4-1%2Ax=2\" Multiply
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\n" ); document.write( " \"-1%2Ax%2B4-1%2Ax=2\" Reduce any fractions
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\n" ); document.write( " \"-1%2Ax-1%2Ax=2-4\" Subtract \"4\" from both sides
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\n" ); document.write( " \"-1%2Ax-1%2Ax=-2\" Combine the terms on the right side
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\n" ); document.write( " \"-2%2Ax=-2\" Now combine the terms on the left side.
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\n" ); document.write( " \"cross%28%281%2F-2%29%28-2%2F1%29%29x=%28-2%2F1%29%281%2F-2%29\" Multiply both sides by \"1%2F-2\". This will cancel out \"-2%2F1\" and isolate x
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\n" ); document.write( " So when we multiply \"-2%2F1\" and \"1%2F-2\" (and simplify) we get
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\n" ); document.write( " \"x=1\" <---------------------------------One answer
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\n" ); document.write( " Now that we know that \"x=1\", lets substitute that in for x to solve for y
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\n" ); document.write( " \"-1%281%29%2B1%2Ay=2\" Plug in \"x=1\" into the 2nd equation
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\n" ); document.write( " \"-1%2B1%2Ay=2\" Multiply
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\n" ); document.write( " \"1%2Ay=2%2B1\"Add \"1\" to both sides
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\n" ); document.write( " \"1%2Ay=3\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F1%29%281%29%29%2Ay=%283%2F1%29%281%2F1%29\" Multiply both sides by \"1%2F1\". This will cancel out 1 on the left side.
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\n" ); document.write( " \"y=3%2F1\" Multiply the terms on the right side
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\n" ); document.write( " \"y=3\" Reduce
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\n" ); document.write( " So this is the other answer
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\n" ); document.write( " \"y=3\"<---------------------------------Other answer
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\n" ); document.write( " So our solution is
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\n" ); document.write( " \"x=1\" and \"y=3\"
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\n" ); document.write( " which can also look like
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\n" ); document.write( " (\"1\",\"3\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"1%2Ax%2B1%2Ay=4\"
\n" ); document.write( " \"-1%2Ax%2B1%2Ay=2\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"1%2Ax%2B1%2Ay=4\" (red) and \"-1%2Ax%2B1%2Ay=2\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
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\n" ); document.write( " and we can see that the two equations intersect at (\"1\",\"3\"). This verifies our answer.
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\n" ); document.write( " Check:
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\n" ); document.write( " Plug in (\"1\",\"3\") into the system of equations
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\n" ); document.write( " Let \"x=1\" and \"y=3\". Now plug those values into the equation \"1%2Ax%2B1%2Ay=4\"
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\n" ); document.write( " \"1%2A%281%29%2B1%2A%283%29=4\" Plug in \"x=1\" and \"y=3\"
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\n" ); document.write( " \"1%2B3=4\" Multiply
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\n" ); document.write( " \"4=4\" Add
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\n" ); document.write( " \"4=4\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"1\",\"3\") satisfies \"1%2Ax%2B1%2Ay=4\"
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\n" ); document.write( " Let \"x=1\" and \"y=3\". Now plug those values into the equation \"-1%2Ax%2B1%2Ay=2\"
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\n" ); document.write( " \"-1%2A%281%29%2B1%2A%283%29=2\" Plug in \"x=1\" and \"y=3\"
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\n" ); document.write( " \"-1%2B3=2\" Multiply
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\n" ); document.write( " \"2=2\" Add
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\n" ); document.write( " \"2=2\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"1\",\"3\") satisfies \"-1%2Ax%2B1%2Ay=2\"
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\n" ); document.write( " Since the solution (\"1\",\"3\") satisfies the system of equations
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\n" ); document.write( " \"1%2Ax%2B1%2Ay=4\"
\n" ); document.write( " \"-1%2Ax%2B1%2Ay=2\"
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\n" ); document.write( " this verifies our answer.
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