document.write( "Question 92331: Please help me I am having some problems with this question this is from a worksheet.\r
\n" ); document.write( "\n" ); document.write( "solve the system by addititon or substitution
\n" ); document.write( "3x + 6y = 0
\n" ); document.write( " x=2/3
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Algebra.Com's Answer #67178 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Lets solve by substitution\r
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\n" ); document.write( "\n" ); document.write( "\"3%282%2F3%29+%2B+6y+=+0\" plug in \"x=2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"2+%2B+6y+=+0\" multiply\r
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\n" ); document.write( "\n" ); document.write( "\"+6y+=+-2\" Subtract -2 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"+y+=+-2%2F6\" Divide both sides by 6\r
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\n" ); document.write( "\n" ); document.write( "\"+y+=+-1%2F3\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=2%2F3\" , \"y=-1%2F3\"
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