document.write( "Question 1056675: -4x+3/8x-1 \n" ); document.write( "
Algebra.Com's Answer #671753 by josgarithmetic(39625)\"\" \"About 
You can put this solution on YOUR website!
What do you want with this? You categorized your posting in Inverse Operations for addition and multiplication, or reciprocals.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "A guess about the expression you really have is that, \"y=%28-4x%2B3%29%2F%288x-1%29\". If you want the function inverse, then a quick way can be exchange x and y and solve for y.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28-4y%2B3%29%2F%288y-1%29=x\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-4y%2B3=8xy-x\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-4y-8xy%2B3=-x\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4y%2B8xy-3=x\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y%284%2B8x%29=x%2B3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=%28x%2B3%29%2F%288x%2B4%29\"
\n" ); document.write( "
\n" );