document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1056637>Question 1056637</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A lab technician wants to mix some amount of a 15% acid solution and another amount of a 25% acid solution so that his resultant mixture is 80 mL of a 22% acid solution. What volume of the 15% acid solution and 25% acid solution is required? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671726 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671726\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A lab technician wants to mix some amount of a 15% acid solution and another amount of a 25% acid solution so that his resultant mixture is 80 mL of a 22% acid solution. What volume of the 15% acid solution and 25% acid solution is required?<BR>\n" );
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document.write( "acid + acid = acid<BR>\n" );
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document.write( "0.15x + 0.25(80-x) = 0.22*80<BR>\n" );
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document.write( "15x + 25*80 - 25x = 22*80<BR>\n" );
document.write( "-10x = -3*80<BR>\n" );
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document.write( "x = 24 mL (amt. of 15% solution needed)<BR>\n" );
document.write( "80-x = 56 mL (amt. 25% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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