document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1056628>Question 1056628</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this question: Find all solutions for 2/3Sin^2-cosx=1 on the interval (0,2pi) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671706 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find all solutions for (2/3)Sin^2-cosx=1 on the interval (0,2pi)<BR>\n" );
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document.write( "(2/3)(1-cos^2(x)) - cos(x) = 1<BR>\n" );
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document.write( "(2/3) - (2/3)cos^2(x) - cos(x) = 1<BR>\n" );
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document.write( "2 - 2cos^2(x) - 3cos(x)  = 3<BR>\n" );
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document.write( "2cos^2(x) + 3cos(x) + 1 = 0<BR>\n" );
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document.write( "(2cos(x) + 1)(cos(x)+1) = 0<BR>\n" );
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document.write( "cos(x) = -1/2 Or cos(x) = -1<BR>\n" );
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document.write( "x = (2/3)pi or x = (4/3)pi or x = pi<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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