document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1056616>Question 1056616</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ohm’s law states that the amount of current that flows through a wire varies inversely as the<BR>\n" );
document.write( "resistance. If a current of 9 amps flows through a wire with a resistance of 2 ohms, then what<BR>\n" );
document.write( "current flows through a wire with a resistance of 3 ohms?\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671696 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671696\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It will be less with more resistance<BR>\n" );
document.write( "I=k/R where I is current and R resistance<BR>\n" );
document.write( "find k first<BR>\n" );
document.write( "9=k/2<BR>\n" );
document.write( "k-18<BR>\n" );
document.write( "use k in the second<BR>\n" );
document.write( "I=18/3=6 amps, which is less. </SPAN>\n" );
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