document.write( "Question 1056540: today a man is 10 years older than twice his sons age.the sum of their age is 55 .what is the father and sons age? \n" ); document.write( "
Algebra.Com's Answer #671658 by ikleyn(52803)\"\" \"About 
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\n" ); document.write( "today a man is 10 years older than twice his sons age.the sum of their age is 55 .what is the father and sons age?
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document.write( "Let \"x\" be the son's age.\r\n" );
document.write( "Then the father's age is 2x+10.\r\n" );
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document.write( "(2x+10) + x = 55,\r\n" );
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document.write( "3x = 55 - 10 = 45\r\n" );
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document.write( "x = \"45%2F3\" = 15.\r\n" );
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document.write( "Answer.  The son is 15 years old, the father is 2*15+10 = 40 years old.\r\n" );
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