document.write( "Question 1056312: Town P and Q are 265 km apart. Car A started from P at 60 km/hr at 8.00 am towards Q. Car B started from Q at 40 km/hr at 10.00 am. B stopped for half an hour. A stopped for 28 minutes at town S which is at a distance of 210 km from P. Find the time at which B crossed A.\r
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document.write( "Explain in simplified way please \n" );
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Algebra.Com's Answer #671578 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Town P and Q are 265 km apart. \n" ); document.write( " Car A started from P at 60 km/hr at 8.00 am towards Q. \n" ); document.write( " Car B started from Q at 40 km/hr at 10.00 am. B stopped for half an hour. \n" ); document.write( " A stopped for 28 minutes at town S which is at a distance of 210 km from P. \n" ); document.write( " Find the time at which B crossed A. \n" ); document.write( ": \n" ); document.write( "P-A>----------------210 km-----------------------S---------55 km----------< B - Q \n" ); document.write( ": \n" ); document.write( "Let's find the time that each of them arrives at S, and see where we are at \n" ); document.write( "A: 210/60 = 3.5 hrs to S \n" ); document.write( "A started at 8:00, so arrives at 11:30 \n" ); document.write( ": \n" ); document.write( "B: 55/40 = 1.375 hrs which is 1 hr 22.5 min travel time to S \n" ); document.write( "B stopped for a half hour so let's assume it left at 10:30 \n" ); document.write( "10:30 + 1:22.5 = 11:52.5 arrives at S \n" ); document.write( ": \n" ); document.write( "A is already there waited for 22.5 min when B arrives \n" ); document.write( ": \n" ); document.write( "A meets S at 11:52.5 \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "Did this make sense to you: CK \n" ); document.write( " |