document.write( "Question 1056323: log (x-1) + log (5) = log (x^2-1)
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Algebra.Com's Answer #671467 by josgarithmetic(39625) $\"\"$ $\"About$

You can put this solution on YOUR website!
log (x-1) + log (5) = log (x^2-1)
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\n" ); document.write( "\n" ); document.write( "This is how to write it properly:
\n" ); document.write( "log(2,(x-1))+log(2,5)=log(2,(x^2-1))\r
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\n" ); document.write( "\n" ); document.write( " $\"log%282%2C%28x-1%29%29%2Blog%282%2C5%29=log%282%2C%28x%5E2-1%29%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"log%282%2C%28x-1%29%285%29%29=log%282%2C%28x%5E2-1%29%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"5%28x-1%29=x%5E2-1\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2-1-5x%2B5=0\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2-5x%2B4=0\"$ , and you can handle the rest... \n" ); document.write( "

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