document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1056297>Question 1056297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> From 13.0 L of coolant containing 13.4% antifreeze, 5.50 L are removed. If 5.50 L of antifreeze are then added, how much antifreeze will be contained in the final mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671446 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2813%2A13.4-5.5%2A13.4%2B5.5%2A100%29%2F13 ALIGN=MIDDLE  ALT=\"%2813%2A13.4-5.5%2A13.4%2B5.5%2A100%29%2F13\"   DISABLED_style= \"max-width:90%; height:auto;\" >, the <b>percent</b> antifreeze in the adjusted solution.   </SPAN>\n" );
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