document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1056250>Question 1056250</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Electricity. The power P in an electric circuit varies directly with the square of the current I. If P = 46 when I = 2, find P when I = 5.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671424 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671424\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Electricity. The power P in an electric circuit varies directly with the square of the current I. If P = 46 when I = 2, find P when I = 5.<BR>\n" );
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document.write( "P = I^2*R<BR>\n" );
document.write( "46 = 4*R<BR>\n" );
document.write( "R = 23/2<BR>\n" );
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document.write( "find P when I = 5.<BR>\n" );
document.write( "P = 25*23/2<BR>\n" );
document.write( "P = 575/2 watts </SPAN>\n" );
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