document.write( "Question 1056223: Carmen was excited about the possibility of earning the \"Mayfield Math Award.\" In order to do this she must have an average score of at least 92 in her first 5 tests. If her first 4 scores were 96, 90, 89, and 97, what is the lowest score Carmen could have on the 5th test and still earn the award? \r
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document.write( "F. 88
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document.write( "G. 89
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document.write( "H. 90
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document.write( "J. 91
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document.write( "K. 92 \n" );
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Algebra.Com's Answer #671408 by addingup(3677)![]() ![]() You can put this solution on YOUR website! add 96, 90, 89, 97 and unknown x and divide by 5: \n" ); document.write( "96+90+89+97+x/5 = 92 \n" ); document.write( "Do this: \n" ); document.write( "Add all the numbers on the left. \n" ); document.write( "Multiply both sides times 5. On the left, times 5/5 cancel each other and you are left with the sum of the numbers+x On the right you will have the product of 92 times 5. \n" ); document.write( "Now subtract the sum on the left from the number on the right. You'll have the x by itself on the left and your answer on the right. \n" ); document.write( " \n" ); document.write( " |