document.write( "Question 1056202: A plane flying the​ 3458-mi from New York City to London has a 70
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\n" ); document.write( "tailwind. The​ flight's point of no return is the point at which the flight time required to return to New York is the same as the time required to continue to London. If the​ plane's speed in still air is 900
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Algebra.Com's Answer #671405 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
speed*time=distance
\n" ); document.write( "The distance the plane is from NY is 970 mph*time in hours, going east\r
\n" ); document.write( "\n" ); document.write( "At any given point, the time required to go to London is distance/speed
\n" ); document.write( "The time required to go back to NY is distance/speed
\n" ); document.write( "To London, we will call the distance x
\n" ); document.write( "To New York, we will call the distance 3458-x
\n" ); document.write( "speed to London is 970 mph
\n" ); document.write( "speed to New York is 830 mph
\n" ); document.write( "Time to London is x/970
\n" ); document.write( "Time to NY is (3458-x)/830
\n" ); document.write( "They are equal.
\n" ); document.write( "(3458-x)/830=x/970
\n" ); document.write( "Cross-multiply
\n" ); document.write( "3354260-970x=830x
\n" ); document.write( "1800x=3354260
\n" ); document.write( "x=1863.48 miles
\n" ); document.write( "The distance to New York requires an extra step since I didn't make the distance x.
\n" ); document.write( "1594.52 miles ANSWER
\n" ); document.write( "at 970 mph, 1863.48 miles is 1.921 hours
\n" ); document.write( "at 830 mph 1594.52 miles is 1.921 hours
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