document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=7252>Question 7252</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please reduce the fraction.   (-20)(t^5)(u^2)(v^3) / (48)(t^7)(u^4)(v)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6714 by </B><A HREF=/tutors/aboutme.mpl?userid=smik><B>smik(40)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=smik><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Good question!<BR>\n" );
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document.write( "(-20)(t^5)(u^2)(v^3) / (48)(t^7)(u^4)(v)<BR>\n" );
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document.write( "considering its the division of these variables, we subtract the power of the variable in the numerator, by the power of the same variable in the denominator. E.g. So: t^5 / t^7 = t^(-2). Furthermore both -20 and 48 are divisible by 4, giving us -5 and 12 respectively.<BR>\n" );
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document.write( "Therefore the above comes down to:<BR>\n" );
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document.write( "(-5)(t^-2)(u^-2)(v^2) / (12)<BR>\n" );
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document.write( "Now the final step is to shift all the negative exponents in the numerator down to the denominator. E.g. 9^-2 = 1/(9^2).<BR>\n" );
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document.write( "So we get (as a final answer):<BR>\n" );
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document.write( "(-5)(v^2) / (12)(t^2)(u^2)\r<BR>\n" );
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