document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1056208>Question 1056208</A>: <I><SPAN STYLE=\"word-break: break-all;\"> through (-1,-1); perpendicular to x+2y=-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671396 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671396\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+ 2Y = -2<BR>\n" );
document.write( "Y = (-1/2)X - 1 Green Line<BR>\n" );
document.write( "m = -1/2<BR>\n" );
document.write( "|New perpendicular Line:  m = 2 (negative reciprocal)<BR>\n" );
document.write( "thru P(-1,-1)<BR>\n" );
document.write( "y + 1 = 2(x+ 1)<BR>\n" );
document.write( "y = 2x + 1  Blue Line<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );