document.write( "Question 1056051: The stopping distance of ,d , of a particular car after the brakes are applied varies directly as the square of the rate .r, if the car is traveling 40 mph , it can stop in 80 feet. how many feet will it take the same car to stop when it is traveling 80 mph ? \n" ); document.write( "
Algebra.Com's Answer #671340 by ankor@dixie-net.com(22740)\"\" \"About 
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The stopping distance of ,d , of a particular car after the brakes are applied varies directly as the square of the rate .r,
\n" ); document.write( "if the car is traveling 40 mph , it can stop in 80 feet.
\n" ); document.write( "r^2 * k = d
\n" ); document.write( "40^2*k = 80
\n" ); document.write( "1600k = 80
\n" ); document.write( "k = 80/1600
\n" ); document.write( "k = .05 the constant of the variation
\n" ); document.write( ":
\n" ); document.write( "\"how many feet will it take the same car to stop when it is traveling 80 mph?\"
\n" ); document.write( "d = .05*80^2
\n" ); document.write( "d = 320 ft to stop at 80 mph
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