document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1056146>Question 1056146</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A wire that is 500M long is used to fence a rectangular field. What are the dimensions of the largest possible rectangular field that can be fenced using the wire? Note: The largest field that can be fenced is the one with the greatest area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671331 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671331\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of the rectangular field, A = l*w<BR>\n" );
document.write( "The perimeter of the fenced in area is 2(l+w) = 500 m<BR>\n" );
document.write( "Express w in terms of l: w = 250 - l<BR>\n" );
document.write( "Therefore A = l(250-l)<BR>\n" );
document.write( "The largest area will be obtained where dA/dl = 0 = 250 - 2l<BR>\n" );
document.write( "Solve for l:<BR>\n" );
document.write( "l = 250/2 = 125 m<BR>\n" );
document.write( "w = 250 - 125 = 125 m<BR>\n" );
document.write( "So length and width are both 125 m, i.e. a square\r<BR>\n" );
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document.write( " </SPAN>\n" );
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