document.write( "Question 1056131: A gave 2/3rd of the amount that he had to B ,B in turn gave 1/4th of what he had received from A to C and C gave Rs 60 to D,which was 1/3rd of what he had received from B .find how much money A had initially? \n" ); document.write( "
Algebra.Com's Answer #671309 by josmiceli(19441)\"\" \"About 
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Let \"+x+\" = the amount A has initially
\n" ); document.write( "A gave \"+%282%2F3%29%2Ax+\" to B
\n" ); document.write( "B gave \"+%281%2F4%29%2A%282%2F3%29%2Ax+=+%28+1%2F6+%29%2Ax+\" to C
\n" ); document.write( "------------------------------------------
\n" ); document.write( "C gives to D:
\n" ); document.write( "\"+60+=+%281%2F3%29%2A%281%2F6%29%2Ax+\"
\n" ); document.write( "\"+%281%2F18+%29%2Ax+=+60+\"
\n" ); document.write( "\"+x+=+18%2A60+\"
\n" ); document.write( "\"+x+=+1080+\"
\n" ); document.write( "A initially had Rs 1,080
\n" ); document.write( "------------------------
\n" ); document.write( "check answer:
\n" ); document.write( "A gave \"+%282%2F3%29%2A1080+=+720+\" to B
\n" ); document.write( "B gave \"+%281%2F4%29%2A720+=+180+\" to C
\n" ); document.write( "\"+60+=+%281%2F3%29%2A180+\"
\n" ); document.write( "\"+60+=+60+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );