document.write( "Question 1056102: A cat on seeing a dog 100m away turns around and start running away at 24 kmph.The dog spots him one minute later and start chasing the cat at a speed of 33kmph.After how much time,from the start of the cat's run,will the chase end?\r
\n" ); document.write( "\n" ); document.write( "Please explain with the help of diagram
\n" ); document.write( "

Algebra.Com's Answer #671301 by MathTherapy(10555)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "A cat on seeing a dog 100m away turns around and start running away at 24 kmph.The dog spots him one minute later and start chasing the cat at a speed of 33kmph.After how much time,from the start of the cat's run,will the chase end?\r
\n" ); document.write( "\n" ); document.write( "Please explain with the help of diagram
\n" ); document.write( "
I don't do diagrams. Sorry. You have to visualize it and draw your own diagram.\r
\n" ); document.write( "\n" ); document.write( "Let time the cat takes to get to the catch point be T
\n" ); document.write( "Then time dog takes to get to catch up point = \"T+-+1%2F60\"
\n" ); document.write( "Since they’re travelling in km, then distance between the 2 is: .1 km (100 m)
\n" ); document.write( "We then get the following DISTANCE equation: \"24T+=+33%28T+-+1%2F60%29+-+.1\"
\n" ); document.write( "\"24T+=+33T+-+11%2F20+-+.1\"
\n" ); document.write( "\"24T+-+33T+=+-+11%2F20+-+1%2F10\"
\n" ); document.write( "480T – 660T = - 11 - 2 -------- Multiplying by LCD, 20
\n" ); document.write( "- 180T = - 13
\n" ); document.write( "T, or time the chase ended (dog caught up), from the time the cat started running = \n" ); document.write( "
\n" );