document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13196>Question 13196</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Problem solving extending charts!\r<BR>\n" );
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document.write( "1. Find the number of full 8 hr. shifts that Maria worked last month<BR>\n" );
document.write( " (1) She worked twice as many 6 hr. shifts as 8 hr. shifts.<BR>\n" );
document.write( " (2) She worked a total of 280 hrs.\r<BR>\n" );
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document.write( "Then you make a chart One column is 6h shifts the other is 8 h shifts. The first row is Hrs. Per shift x Number of shifts = Total hrs. worked. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6713 by </B><A HREF=/tutors/aboutme.mpl?userid=bam878s><B>bam878s(77)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bam878s><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=number of 8hr shifts and y=number of 6hr shifts.<BR>\n" );
document.write( "Note y=2x<BR>\n" );
document.write( "we have 8x+6y=280<BR>\n" );
document.write( "sub for y<BR>\n" );
document.write( "8x+6(2x)=280<BR>\n" );
document.write( "8x+12x=280<BR>\n" );
document.write( "20x=280<BR>\n" );
document.write( "divide both sides by 20 to get<BR>\n" );
document.write( "x=14 8hr shifts<BR>\n" );
document.write( "y=14*2=28 6hr shifts </SPAN>\n" );
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