document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1056115>Question 1056115</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If cot(x)=-2 and cos(x)>0 find the exact value of cos(x/2) \r<BR>\n" );
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document.write( "I tried working it out based on where it would be on the graph from the cot(x) value and the Cos(x) being greater then 0 <BR>\n" );
document.write( "From there I tried to use conversions and just got lost. Any help to figure this out would be great.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671285 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671285\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First value tells you that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cosine%28x%29%2Fsin%28x%29%3C0 ALIGN=MIDDLE  ALT=\"cosine%28x%29%2Fsin%28x%29%3C0\"   DISABLED_style= \"max-width:90%; height:auto;\" > and that means quadrant 2 or quadrant 4.  Second part, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cosine%28x%29%3E0 ALIGN=MIDDLE  ALT=\"cosine%28x%29%3E0\"   DISABLED_style= \"max-width:90%; height:auto;\" > means quadrant 1 or quadrant 4.  The conclusion to make for what is common, is x is in quadrant 4.\r<BR>\n" );
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document.write( "You can draw a simple right triangle with radius endpoint in the quadrant 4 to help you further.  Radius, or hypotenuse, is 1; horiZontal coordiante 2*k; vertical component or coordinate -1*k.  You can also say,  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%28x%29=-1%2F2 ALIGN=MIDDLE  ALT=\"tan%28x%29=-1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "x is arc whose tangent is negative one-half. </SPAN>\n" );
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