document.write( "Question 1056086: A 57-foot wire is cut into three pieces. The second piece if 7 feet longer than the first piece and the third piece is twice as long as the second piece. How long is each piece? \n" ); document.write( "
Algebra.Com's Answer #671255 by stanbon(75887)\"\" \"About 
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A 57-foot wire is cut into three pieces. The second piece if 7 feet longer than the first piece and the third piece is twice as long as the second piece. How long is each piece?
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\n" ); document.write( "1st piece:: x ft
\n" ); document.write( "2nd piece:: x+7 ft
\n" ); document.write( "3rd piece:: 2(x+7) = 2x+14
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\n" ); document.write( "Equation:
\n" ); document.write( "x + (x+7) + (2x+14) = 57 ft
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\n" ); document.write( "4x + 21 = 57
\n" ); document.write( "4x = 36
\n" ); document.write( "x = 1st = 9 ft
\n" ); document.write( "2nd piece = x+7 = 16 ft
\n" ); document.write( "3rd piece = 2(x+7) = 32 ft
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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