document.write( "Question 1056082: Chuck kayaked 4 miles upstream in
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document.write( "the same time it took him to kayak 10
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document.write( "miles downstream. If the speed of the
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document.write( "current is 3 mph, what is Chuck’s speed in
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document.write( "still water? \n" );
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Algebra.Com's Answer #671254 by jorel555(1290) ![]() You can put this solution on YOUR website! Let n be Chuck's rate in still water. Then: \n" ); document.write( "4/n-3=10/n+3 \n" ); document.write( "4n+12=10n-30 \n" ); document.write( "6n=42 \n" ); document.write( "n=7 mph as Chuck's rate in still water.☺☺☺☺ \n" ); document.write( " |