document.write( "Question 1056082: Chuck kayaked 4 miles upstream in
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document.write( "the same time it took him to kayak 10
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document.write( "miles downstream. If the speed of the
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document.write( "current is 3 mph, what is Chuck’s speed in
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document.write( "still water? \n" );
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Algebra.Com's Answer #671253 by Boreal(15235) You can put this solution on YOUR website! v1*t1=distance \n" ); document.write( "(x-3)*t1=4 \n" ); document.write( "t1=4/(x-3) \n" ); document.write( "v2*t1=10 \n" ); document.write( "(x+3)*t1=10 \n" ); document.write( "t1=10/(x+3) \n" ); document.write( "set the two times, which are the same, equal to each other. \n" ); document.write( "4/(x-3)=10/(x+3) \n" ); document.write( "Cross-multiply \n" ); document.write( "10x-30=4x+12 \n" ); document.write( "6x=42 \n" ); document.write( "x=7 mph ANSWER \n" ); document.write( "downstream at 10 mph, counting current, and it takes him 1 hour to do 10 miles \n" ); document.write( "upstream at 4 mph, counting current, and it takes him 1 hour to do 4 miles.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |