document.write( "Question 1056059: David has a total of $4.25. He has twice as many dimes as nickels. The number of quarters that he has is three less than the number of nickles. how many of each coin does he have \n" ); document.write( "
Algebra.Com's Answer #671240 by stanbon(75887)\"\" \"About 
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David has a total of $4.25. He has twice as many dimes as nickels. The number of quarters that he has is three less than the number of nickles. how many of each coin does he have?
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\n" ); document.write( "Value Eq:: 5n + 10d + 25q = 425 cents
\n" ); document.write( "Quantity:: q = n-3
\n" ); document.write( "Quantity:: d = 2n
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\n" ); document.write( "Divide through the 1st by 5
\n" ); document.write( "Substitute for \"q\" and for \"d\"
\n" ); document.write( "Solve for \"n\"::
\n" ); document.write( "n + 2d + 5q = 85
\n" ); document.write( "n + 2(2n) + 5(n-3) = 85
\n" ); document.write( "10n - 15 = 85
\n" ); document.write( "10n = 100
\n" ); document.write( "n = 10 (# of nickels)
\n" ); document.write( "d = 2n = 20 (# of dimes)
\n" ); document.write( "q = n-3 = 7 (# of quarters)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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