document.write( "Question 1056026: How many gallons of a 50% antifreeze solution must be mixed with 70 gallons of 10% antifreeze to get a mixture that is 40% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #671191 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many gallons of a 50% antifreeze solution must be mixed with 70 gallons of 10% antifreeze to get a mixture that is 40% antifreeze? \n" ); document.write( "---------------- \n" ); document.write( "active + active = active \n" ); document.write( "0.5x + 0.10*70 = 0.4(x+70) \n" ); document.write( "--------------------------- \n" ); document.write( "50x + 10*70 = 40x + 40*70 \n" ); document.write( "10x = 30*70 \n" ); document.write( "---- \n" ); document.write( "x = 210 gallons (amt of 50% antifreeze needed) \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------- \n" ); document.write( " |