document.write( "Question 1056026: How many gallons of a 50% antifreeze solution must be mixed with 70 gallons of 10% antifreeze to get a mixture that is 40% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #671191 by stanbon(75887)\"\" \"About 
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How many gallons of a 50% antifreeze solution must be mixed with 70 gallons of 10% antifreeze to get a mixture that is 40% antifreeze?
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\n" ); document.write( "active + active = active
\n" ); document.write( "0.5x + 0.10*70 = 0.4(x+70)
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\n" ); document.write( "50x + 10*70 = 40x + 40*70
\n" ); document.write( "10x = 30*70
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\n" ); document.write( "x = 210 gallons (amt of 50% antifreeze needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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