document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1056030>Question 1056030</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mackenzie invests $800 in one account and $2400 in an account paying 3 % higher interest. At the end of one year she had earned $264 in interest. At what rates did she invest? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671189 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671189\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mackenzie invests $800 in one account and $2400 in an account paying 3 % higher interest. At the end of one year she had earned $264 in interest. At what rates did she invest? <BR>\n" );
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document.write( "interest + interest = interest<BR>\n" );
document.write( "800(x/100) + 2400(x+3)/100 = 264<BR>\n" );
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document.write( "800x + 2400x + 7200 = 26400<BR>\n" );
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document.write( "3200x = 19200<BR>\n" );
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document.write( "x = 6%<BR>\n" );
document.write( "(interest on the $800)<BR>\n" );
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document.write( "x+3 = 9%  (interest on the $2400)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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