document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1056021>Question 1056021</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a father is 42 years old. his children are 6,8 and 12 years old respectively. how old will the father be when his age equals the sum of his three children's ages ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671183 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a father is 42 years old. his children are 6,8 and 12 years old respectively. how old will the father be when his age equals the sum of his three children's ages ?<BR>\n" );
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document.write( "respectively?<BR>\n" );
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document.write( "The sum of their ages is 26<BR>\n" );
document.write( "The sum increases 3 years per year.<BR>\n" );
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document.write( "26 + 3y = 42 + y<BR>\n" );
document.write( "2y = 16<BR>\n" );
document.write( "y = 8 years<BR>\n" );
document.write( "----<BR>\n" );
document.write( "--> 14 + 16 + 20 = 42 + 8<BR>\n" );
document.write( " </SPAN>\n" );
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