document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92260>Question 92260</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the park is a perfect right triangle. its hypotenuse is 40m long one leg of the triangle is 8 m shorterthan the other leg. find the length of each leg of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67115 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67115\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the park is a perfect right triangle. its hypotenuse is 40m long one leg of the triangle is 8 m shorterthan the other leg. find the length of each leg of the triangle.<BR>\n" );
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document.write( "Let one of the legs be \"x\" ; Let the other leg be \"x-8\"<BR>\n" );
document.write( "Use Pythagoras to get:<BR>\n" );
document.write( "x^2 + (x-8)^2 = 40^2<BR>\n" );
document.write( "x^2 + x^2-16x+64 = 1600<BR>\n" );
document.write( "2x^2-16x+64 = 1600<BR>\n" );
document.write( "x^2-8x-768=0<BR>\n" );
document.write( "(x-32)(x+24)=0<BR>\n" );
document.write( "Positive answer:<BR>\n" );
document.write( "x= 32 meters (the longer leg)<BR>\n" );
document.write( "x-8 = 24 meters (the shorter leg)\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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