document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1055939>Question 1055939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A computer salesman averages 0.9 sales per week. Use the Poisson distribution to find that in a randomly selected week the number of sales sold is 1. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671148 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671148\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The mean and the variance of the Poisson are the same, and 1 is very near the mean, so there should be a reasonably significant probability, although the variance/sd are both 1.  There will be a significant tail<BR>\n" );
document.write( "P(1)=e(^-0.9)(0.9)^1/1!<BR>\n" );
document.write( "That is 0.9*e^(-0.9)=0.3659\r<BR>\n" );
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