document.write( "Question 1055986: Can you, please, help me write this sequence of numbers in summation notation? Thank you! 12+4+4/3+4/9. \n" ); document.write( "
Algebra.Com's Answer #671147 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! sum (12/3^(n-1)), with n running from 1 to 4 \n" ); document.write( "n=1, value is 12/1 \n" ); document.write( "n=2, value is 12/3=4 \n" ); document.write( "n=3, value is 12/9=4/3 \n" ); document.write( "n=4, value is 12/27=4/9 \n" ); document.write( " |