document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1055975>Question 1055975</A>: <I><SPAN STYLE=\"word-break: break-all;\"> `If <1 and <2 are complementes and m<1= (5y +1) and m<2= (3y-7) find the value of y?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671132 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The two angles are complementary angles. By definition, they add to 90 degrees. \r<BR>\n" );
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document.write( "(measure of angle 1) + (measure of angle 2) = 90<BR>\n" );
document.write( "(5y+1) + (3y-7) = 90<BR>\n" );
document.write( "5y+1 + 3y-7 = 90<BR>\n" );
document.write( "(5y+3y) + (1-7) = 90<BR>\n" );
document.write( "8y - 6 = 90<BR>\n" );
document.write( "8y - 6+6 = 90+6<BR>\n" );
document.write( "8y = 96<BR>\n" );
document.write( "8y/8 = 96/8<BR>\n" );
document.write( "y = 12\r<BR>\n" );
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