document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1055965>Question 1055965</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A scientist begins with 100 milligrams of a radioactive substance that decays exponentially. After 36 hours, 50 mg of the substance remains. How many milligrams will remain after 52 hours ? <BR>\n" );
document.write( "_________ mg </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671127 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671127\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A scientist begins with 100 milligrams of a radioactive substance that decays exponentially. After 36 hours, 50 mg of the substance remains.<BR>\n" );
document.write( "y = a*b^x<BR>\n" );
document.write( "50 = 100*b^36<BR>\n" );
document.write( "b = 0.5^(1/36)<BR>\n" );
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document.write( " How many milligrams will remain after 52 hours ? <BR>\n" );
document.write( "f(x) = 100*(0.5)^(x/36)<BR>\n" );
document.write( "f(52) = 100*(0.5)^(52/36) = 36.74 mg<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------- </SPAN>\n" );
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