document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1055968>Question 1055968</A>: <I><SPAN STYLE=\"word-break: break-all;\"> `If <1 and <2 are complementary angles and m<1= (2x+20) and m<2= (3x +15)  find the value of x? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671122 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671122\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> `If <1 and <2 are complementary angles and m<1= (2x+20) and m<2= (3x +15) find the value of x? <BR>\n" );
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document.write( "Equation::<BR>\n" );
document.write( "(2x+20) + (3x+15) = 90 degrees<BR>\n" );
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document.write( "5x + 35 = 90<BR>\n" );
document.write( "5x = 55 <BR>\n" );
document.write( "x = 11<BR>\n" );
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document.write( "<1 = 2x+20 = 22+20 = 42 degrees<BR>\n" );
document.write( "<2 = 3x+15 = 33+15 = 48 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );