document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1055918>Question 1055918</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A craftperson has two alloys of silver. The first on is 70% pure silver and the second one is 50% silver. How many kilograms of each must be mixed to have 12kg of an alloy which is 65% silver? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671073 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671073\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x the amount of the 70% solution<BR>\n" );
document.write( "Question States:<BR>\n" );
document.write( ".70x + .50(12kg-x) = .65(12kg)<BR>\n" );
document.write( "x = .15(12kg)/.20<BR>\n" );
document.write( "find x, amount of the 70% solution<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12kg+-+x ALIGN=MIDDLE  ALT=\"12kg+-+x\"   DISABLED_style= \"max-width:90%; height:auto;\" > = amount of the 50% solution </SPAN>\n" );
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