document.write( "Question 1055859: Farmers mowed 60 acres of grass a day instead of 50 and managed to finish the task one day earlier than planned. What is the area of the meadow they were mowing? \n" ); document.write( "
Algebra.Com's Answer #671050 by ikleyn(52805)\"\" \"About 
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\n" ); document.write( "Farmers mowed 60 acres of grass a day instead of 50 and managed to finish the task one day earlier than planned.
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document.write( "The direct translation the condition to math is this equation\r\n" );
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document.write( "\"x%2F50+-+x%2F60\" = 1,\r\n" );
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document.write( "where \"x\" is the area under the question.\r\n" );
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document.write( "\"x%2F50\" is the time required to complete the job mowing 50 acres per day.\r\n" );
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document.write( "\"x%2F60\" is the time required to complete the job mowing 60 acres per day.\r\n" );
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document.write( "1 on the right is the time difference, according to the condition.\r\n" );
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document.write( "Mulpiply both sides by LCD(50,60) = 300. You will get\r\n" );
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document.write( "6x - 5x = 300,\r\n" );
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document.write( "1x = 300  --->  x = 300.\r\n" );
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document.write( "Answer.  The area of the meadow they were mowing was 300 acres.\r\n" );
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