document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1055797>Question 1055797</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A store mixes Brazilian coffee worth $11 per kilogram and Turkish coffee worth <BR>\n" );
document.write( "$14 per kilogram. The mixture is to sell for $13 per kilogram. \r<BR>\n" );
document.write( "\n" );
document.write( "Find how much of each should be used to make a 528&#8203;-kilogram mixture. \r<BR>\n" );
document.write( "\n" );
document.write( "How many kilograms of the Brazilian coffee should be in the &#8203;mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #671026 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=671026\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A store mixes Brazilian coffee worth $11 per kilogram and Turkish coffee worth <BR>\n" );
document.write( "$14 per kilogram. The mixture is to sell for $13 per kilogram. <BR>\n" );
document.write( "Find how much of each should be used to make a 528&#8203;-kilogram mixture. <BR>\n" );
document.write( "How many kilograms of the Brazilian coffee should be in the &#8203;mixture? <BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "value + value = value<BR>\n" );
document.write( "11x + 14(528-x) = 13*528<BR>\n" );
document.write( "------------------------------<BR>\n" );
document.write( "11x + 14*528 - 14x = 13*528<BR>\n" );
document.write( "----------------------------------<BR>\n" );
document.write( "-3x = -528<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "x = 176 kg (amt of $11 coffee needed)<BR>\n" );
document.write( "528-x = 352 kg (amt of $14 coffee needed)<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );