document.write( "Question 1055726: The width of a rectangle is 9ft more than 3 times the length. Find the dimensions of the rectangle of the perimeter is 50ft \n" ); document.write( "
Algebra.Com's Answer #670943 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Commonly used and commonly accepted way of using the terms \"width\" and \"length\" is this:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In a rectangle, the length is the greater of two dimensions, while the width is the smaller of two dimensions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The given condition violates this commonly accepted way.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, in my view, the right place of this problem is in TRASH section with the WARNING issued to the author.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |