document.write( "Question 1055726: The width of a rectangle is 9ft more than 3 times the length. Find the dimensions of the rectangle of the perimeter is 50ft \n" ); document.write( "
Algebra.Com's Answer #670942 by addingup(3677)![]() ![]() You can put this solution on YOUR website! W = 3L+9 \n" ); document.write( "2L+2(3L+9) = 50 \n" ); document.write( "2L+6L+18 = 50 \n" ); document.write( "8L = 32 \n" ); document.write( "L = 4 \n" ); document.write( "W = 3(4)+9 = 21 \n" ); document.write( " |