document.write( "Question 1055726: The width of a rectangle is 9ft more than 3 times the length. Find the dimensions of the rectangle of the perimeter is 50ft \n" ); document.write( "
Algebra.Com's Answer #670942 by addingup(3677)\"\" \"About 
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W = 3L+9
\n" ); document.write( "2L+2(3L+9) = 50
\n" ); document.write( "2L+6L+18 = 50
\n" ); document.write( "8L = 32
\n" ); document.write( "L = 4
\n" ); document.write( "W = 3(4)+9 = 21
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