document.write( "Question 1055736: Using the point-slope form linear equation y-3=3(x+1),what is the slope of the given line,and what point does this line pass through,which is the basis of this equation?\r
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Algebra.Com's Answer #670935 by MathTherapy(10552)\"\" \"About 
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Using the point-slope form linear equation y-3=3(x+1),what is the slope of the given line,and what point does this line pass through,which is the basis of this equation?\r
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Point-slope form: \"y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29\"
\n" ); document.write( "Compare to: y - 3 = 3(x + 1)
\n" ); document.write( "You should see that:
\n" ); document.write( "Thus, \"matrix%281%2C6%2C+y+=+3%2C+%22%2C%22%2C+m+=+3%2C+%22%2C%22%2C+and%2C+x+=+-+1%29\"
\n" ); document.write( "Slope = m = 3, and point this line passes through is: (x, y), or (- 1, 3) \n" ); document.write( "
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