document.write( "Question 1055734: i have to 2 equations x+y=20 and 25x+15y=430. the end goal is to find how many of x and y there is. i think i need to cancel out the 15 but i dont know where to start. \n" ); document.write( "

Algebra.Com's Answer #670934 by MathTherapy(10552) $\"\"$ $\"About$

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i have to 2 equations x+y=20 and 25x+15y=430. the end goal is to find how many of x and y there is. i think i need to cancel out the 15 but i dont know where to start.
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x + y = 20 ------- eq (i)
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document.write( "25x + 15y = 430 ------- eq (ii)
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document.write( "You can multiplying eq (i) by - 15 to ELIMINATE y and find the value of x
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document.write( "Then substitute value of x into eq (i) (easier of the 2) to get value of y
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document.write( "OR
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document.write( "Divide eq (ii) by 5 to get: 5x + 3y = 86 ------ eq (ii). 
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document.write( "Then multiply eq (i) by - 3 to get eq (iii), which you then add to eq (ii) to ELIMINATE y and find the value of x.
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document.write( "You'd have 1 more equation to change but after all, you'd be dealing with smaller numbers. It's your choice though. \n" );
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