document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1055713>Question 1055713</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The population of a town increased by 16 2/3% in 1990 and by 10% in 1991. If the population of the town at the beginning of 1990 was 30,000, what was it at the end of 1991?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #670932 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=670932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 16 2/3% is 1/6<BR>\n" );
document.write( "Population was 30,000 and increase of 1/6 is an increase of 5000.  So the population in 1991 is 35,000.<BR>\n" );
document.write( "That increases 10% that year, which is 3500, 10% of the new population.  At the end of 1991, the population is 38,500. </SPAN>\n" );
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