document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1055734>Question 1055734</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i have to 2 equations x+y=20 and 25x+15y=430. the end goal is to find how many of x and y there is. i think i need to cancel out the 15 but i dont know where to start.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #670929 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=670929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=20<BR>\n" );
document.write( "25x+15y=430.<BR>\n" );
document.write( "Multiply the top equation by -15<BR>\n" );
document.write( "-15x-15y=-300<BR>\n" );
document.write( "25x+15y=430<BR>\n" );
document.write( "add them and the y disappear<BR>\n" );
document.write( "10x=130<BR>\n" );
document.write( "divide by 10<BR>\n" );
document.write( "x=13<BR>\n" );
document.write( "Put into first equation and 13+y=20; y=7<BR>\n" );
document.write( "Check with the second equation<BR>\n" );
document.write( "25(13)+15(7)=325+105=430<BR>\n" );
document.write( "(13,7)<BR>\n" );
document.write( "Note, you could multiply the first equation by -25, and then when you added, you would eliminate the x s and get the y.  You eliminate whatever appears to be easier. </SPAN>\n" );
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